The Fixed BB-71

Robert Yemola

BB-71

A- 1, 4, 7, 10, 13

The first thing that you want to do is put this in a chart so it is easier to understand.

N 0 1 2 3 4
T(N) 1 4 7 10 13
The first thing that you want to do is look at the numbers and see if there is a pattern to get from one number to the next. In this case each time you have to +3 each time.
Then to make an equation you to find out if there is a starting point, in this case there is and the starting point is 1. Then you have to plug in the information, T(N)=1+3N you can plug in one to make sure it is correct T(N)=1+3(3) and you get 10 so we know that this equation is correct. Then finally since it adds by the same number each time the equation is Arithmetic.

B- 0, 5, 12, 21, 32

Once again put the numbers into a chart so it is easier to understand.

N 0 1 2 3 4
T(N) 0 5 12 21 32
The first thing you want to do is see if you can find a pattern, you do see a pattern and it is that every time it adds by an odd number. But the thing about that is that, that is neither Arithmetic or Geometric so the Answer to this one is Neither.

C- 2, 4, 8, 16, 32

Put all of the numbers into a table

N 0 1 2 3 4
T(N) 2 4 8 16 32
The first thing you do is look to see if you can find any patterns and you can each time you are multiplying by 2. To make the equation what you would have to do is you would first have to find the starting point which is 2. Then you would put all of the info in and the equation would be T(N)= 2*2^N. Then finally we know that this equation is Geometric because the Equation has an Exponent in it.


D- 5, 12, 19, 26,

Put the numbers into a chart so that they are easier to understand

N 0 1 2 3
T(N) 5 12 19 26
The first thing that you would want to do is try to find a pattern and in this case we can see that every time you have to add 7 to get to the next number. Then to get the Equation you need to find the starting point and in this case the starting point is 5. So the equation for this set of numbers would be T(N)=5+7N. Finally we know that this set of numbers is Arithmetic because each time you have to add the same number.

E- x, x+1, x+2, x+3

Put the numbers in a chart so they are easier to understand

N 0 1 2 3
T(N) X X+1 X+2 X+3
First you want to see if you can find a pattern and you see that the X stays the same. The N is what is added each time. To make this equation you need to find the starting point and this starting point is X. So this equation would be pretty simple T(N)=X+N. Finally we know that this is an Arithmetic equation because each time you add the same thing in this case you add N every time.

F- 3, 12, 48, 192

Put the numbers in a chart so that they are easier to understand

N 0 1 2 3
T(N) 3 12 48 192
The first thing that you want to look at is if there is a pattern to get from one number to the next number. In this case we can see that each time you have to multiply the previous number by 4. Then to get the equation, you need to find the starting point and in this case the starting point is 3. So the equation would be T(N)= 3*4^N. Finally this equation is Geometric because the equation has an exponent in it.

Class Notes 12/11/07

Here are a few of the class problems. There are some mistakes.

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Triangles

The two triangles are similar. They both share a common angle and the smaller one is inside the larger one. For instance two triangles of the same angle degrees intwine. The small triangle has sides of 3 and 5. The large triangle has sides of 8 and an unknown number we should call "z". Our job is to find out what "z" is.



8/3 = z/5
8/3 = 2.6
2.6 * 5 = 13.3

Class Notes 12/10/07

Here are the notes from class.

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BB95 Explantion

First you have to write out the problem in equation form. Once you have did that you can set the equation equal. A good idea for setting this type of equation equal is to distribute. Now the problem will become more simple now all you have to do is isolate one of the variables because in this case there are two variables. Once one varaible is isolated you just solve and then plug in the answer you get in the second equation and solve.

1st equation- 4s+3b = 4.36
2nd equation- 8s+1b = 3.32

Plugging in the 2Nd equation.......

-3(8s+1b) = 3.32(-3)
-24 + 3b = -9.96
+ 4s + 3b = 4.36
_____________________

-20s = -5.6
___ ____
-20 -20

s= 0.28 / 1 can of soup = $0.28


Plug in the 1st equation

4(0.28)+ 3b = 4.36
1.12 + 3b = 4.36
-1.12 -1.12
____________________

3b = 3.24
___ _____
3 3

b = 1.08 / 1loaf of bread =1.0