Scripe post for January 31st

Mr. Rochester demonstrated again what we had to do for the first part of our benchmark. Then after we collected our materials we all went out in the halls and set to work. With our balloons taped on to ours sticks and tape measures in hand the jumping began. Most groups started with the "broad jump" where you stood still and had to jump as high and as far as you could (you had to touch the balloon). then it was full speed ahead to the "long jump". Here you got to have a running start (still had to touch the balloon). Some groups even thought they were so good it was worth filming (oh wait Rochester said it would be a nice addition to our graphs... so never mind everyone should film at some point). So over all today SLA's recored for both the long jump and the broad jump was broken, or i guess set. We will have to find out though when benchmarks are due who holds it though.

For those of you who missed this sports filled class you should talk to your group members and set up a time when they can help you collect your data.

next time on Scribe Post we will have Sam reporting from the right side of the room. Thanks for tuning in to another Scribe Post, until next time.

What I still think we need to review

onI think that before the test on friday we need to work more on the word problems and how to read them so we set up the equations correctly and get the problem.
Also the problems with factoring things and multiplying them out with funky exponents in them. for example FX-112

EF-122- Square root functions

Alison Campbell
Square root functions

You cannot take the square root of a negative number as it will be an imaginary number.

When dealing with square root equations you have to think of the problem as two separate equations, other wise it will not be an equation, due to the vertical line rule. The vertical line rule tells us that we cannot have a line graphed that a vertical line would go through twice. Therefore you have to treat it as two equations.

When it is y= √(x-4) the x- intercept is 4, when it is y=√(x+4) the x intercept is -4. This is because to find the x-intercept of a line you solve the equation for y=0. See Greg’s post on intercepts for more info on finding x and y intercepts.

When you divide a square root, the slope of the line will flatten out towards the x-axis.

The graph looks like half a parabola, turned 90 degrees

Regular problem:
y= √(4x2) Solve for x
y2= +/-4x2 To get ride of the square root you square both sides and add +/-
y=+/- 2x Simplify and get ride of the squares
x=y/2 Get ride of the 2x by dividing both sides by 2

EF-122:
y=√x+4 Solve for x intercept
0=√x+4 set y to 0
0=√-4+4 find the number that will make the right side 0
x= -4

y=√0+4 Solve for y intercept
y=√4 set x to 0
y= +/-2 Simplify and get ride of the square root